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30. You need the random python module which is part of your standard library. Use the code... from random import randint. num1= randint(0,9) This will set the variable num1 to a random number between 0 and 9 inclusive. answered Apr 1, 2021 at 10:09. SamTheProgrammer.
I know how to generate a random number within a range in Python. random.randint(numLow, numHigh) And I know I can put this in a loop to generate n amount of these numbers. for x in range (0, n): listOfNumbers.append(random.randint(numLow, numHigh)) However, I need to make sure each number in that list is unique.
Is there a simple way in Python to generate a random number in a range excluding some subset of numbers in that range? For example, I know that you can generate a random number between 0 and 9 with: from random import randint randint(0,9)
@wjandrea yeah I'm aware that Python 3 range produces a generator. Back when I posted that comment if you tried sample = random.sample(range(1000000000000000000), 10) you could watch the memory of the process grow as it tried to materialize the range before extracting a sample. Checking now with Python 3.10 that appears to have been implemented ...
import random random.uniform(a, b) # range [a, b) or [a, b] depending on floating-point rounding Python provides other distributions if you need. If you have numpy imported already, you can used its equivalent: import numpy as np np.random.uniform(a, b) # range [a, b)
It should be r = list (range (1,n)) + list (range (n+1, end)) (source: Python - Unsupported type (s) : range and range) While other answers are correct. The use of intermediate lists is inefficient. Alternate Solution: Another way you could do this is by choosing randomly from a range of numbers that is n-1 in size.
One might have expected it to work like range, and produce a random number a <= n < b. (Note the closed upper interval.) (Note the closed upper interval.) Given the responses in the comments about randrange , note that these can be replaced with the cleaner random.randrange(0,10**n) , random.randrange(10**(n-1),10**n) and random.randrange(1,10) .
It then produces a random integer within that range. Then it adds to that integer depending on where it is relative to the ranges. Example: If the ranges are (1,3) and (5,9), where ranges are inclusive. Summing the length of all ranges gives 3+4=7. We then create a random integer between 1 and 7 (or 0 and 6).
78. The only differences between randrange and randint that I know of are that with randrange([start], stop[, step]) you can pass a step argument and random.randrange(0, 1) will not consider the last item, while randint(0, 1) returns a choice inclusive of the last item. So, I don't understand why randrange(0, 1) doesn't return 0 or 1.
And I would like to pick a random number within that range. Again, that range is defined as 100:100:20000. Furthermore, by saying 'within that range', I don't mean randomly picking a number from 100->20000, such as 105. I mean randomly choosing a number from the list of numbers available, and that list is defined as 100:100:20000.