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  2. 744. You can use the DISTINCT keyword within the COUNT aggregate function: SELECT COUNT(DISTINCT column_name) AS some_alias FROM table_name. This will count only the distinct values for that column. edited Aug 28, 2013 at 13:46. rstackhouse. 2,316 25 29. answered Sep 26, 2008 at 19:54. Noah Goodrich.

  3. Count all the DISTINCT program names by program type and push number. Count(DISTINCT program_name) AS [Count], DISTINCT COUNT(*) will return a row for each unique count. What you want is COUNT(DISTINCT <expression>): evaluates expression for each row in a group and returns the number of unique, non-null values.

  4. SQL count(*) and distinct - Stack Overflow

    stackoverflow.com/questions/1826120

    COUNT () takes no parameters and cannot be used with DISTINCT. COUNT () does not require an expression parameter because, by definition, it does not use information about any particular column. COUNT (*) returns the number of rows in a specified table without getting rid of duplicates. It counts each row separately.

  5. SELECT COUNT(DISTINCT (DocumentId, DocumentSessionId)) FROM DocumentOutputItems; If your database doesn't support this, it can be simulated as per @oncel-umut-turer's suggestion of CHECKSUM or other scalar function providing good uniqueness e.g. COUNT(DISTINCT CONCAT(DocumentId, ':', DocumentSessionId)).

  6. SQL distinct and count - Stack Overflow

    stackoverflow.com/questions/913302

    You may want to try something like. SELECT Date, Phone, Count(*) As Count From Calls GROUP BY Date, Phone. This will give you a tally of each phone number on each date, with how many times that number appeared on that date. answered May 26, 2009 at 23:39.

  7. sql - COUNT DISTINCT with CONDITIONS - Stack Overflow

    stackoverflow.com/questions/14048098

    2. Try the following statement: select distinct A.[Tag], count(A.[Tag]) as TAG_COUNT, (SELECT count(*) FROM [TagTbl] AS B WHERE A.[Tag]=B.[Tag] AND B.[ID]>0) from [TagTbl] AS A GROUP BY A.[Tag] The first field will be the tag the second will be the whole count the third will be the positive ones count.

  8. My SQL DISTINCT and count if. 1. MySQL query DISTINCT, COUNT. 0. MySQL - Count only if unique. 1.

  9. Since the COUNT aggregate function returns a count of all the records in a field, and the DISTINCT keyword selects only unique records, the combination of COUNT(DISTINCT table_name.users) returned the exact result I expected - the total number of distinct records from the Users field. Again, thank you all for your help :) –

  10. I received an excellent answer: A crosstab can do (from an original proposition from Steve Dassin) as long as you count either the fund, either the subfund: TRANSFORM COUNT(*) AS theCell. SELECT ValDate, COUNT(*) AS StandardCount, COUNT(theCell) AS DistinctCount. FROM tableName.

  11. Considering the same table this could give the result. SELECT EmailAddress, CustomerName FROM Customers as a. Inner Join Customers as b on a.CustomerName <> b.CustomerName and a.EmailAddress = b.EmailAddress. For still better results I would suggest you to use CustomerID or any unique field of your table.