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See tutors like this. First change 20% to a decimal by moving the decimal point two places to the left. So, 20% = .20 = .2 (two-tenths) Now write .2 in fraction form. .2 = 2/10. Reduce 2/10 = 1/5. Upvote • 0 Downvote.
So 125% = 125/100. That can be reduced to 5/4. To convert to a decimal, you can do long division, dividing 5 into 4. Or, you can realize 5/4 = 1 and 1/4, = 1.25. 125/100 is easier to see as a decimal. 125/100 = 1 and 25/100. "25 hundredths" is written down exactly as it is said 0.25, with the digit 5 in the hundredths place of the decimal.
Quanny H. asked • 09/12/18 If 20% of the substance disappears in 10 years, what is its half-life? (Round your answer to two
Statistics Auestion Binomial Distribution. A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 17 randomly selected pens yields no more than two defective pens. (a) Find the probability that this shipment is accepted if 10% of the total shipment is defective. (Use 3 decimal places.)
Treena, if there was a 20% discount, then you paid 80% of the original price. Since we don't know the orginal price, we will assign it the variable x. Change 80% to a decimal. The equation would be:.8x = 276 To get the variable by itself, divide each side by .8..8x/.8 = 276/.8. x = 345. The original price of the suit was $345. Hope this is helpful.
The problem 20% of 10 is a multiplication problem because you want something of something. Note: 20% = 0.20 = 20/100 = 1/5. 0.20 x 10 = 2 revisit the rule for multiplying decimal or. 20/ 100 x 10 / 1 = 200/100 = 2 revisit the rule for multiplying fractions or. diagram 10 divided into 5 parts which have 2 in each equal part.
The number of liters of acid in 200 liters of a 44% acid solution is 0.44 x 200. The sum of the acid in the 20% solution and the 60% solution is equal to the number of liters of acid in the 44% solution, so . 0.20 X + 0.60 Y = 0.44 x 200. Also, X + Y = 200 as the two solutions were mixed together.
I assume that the probability of defective products is 20%. I ignored the statement: "5% defective products" Number of de fective parts = .2 * 700 = 140. Number of good parts = .8 * 700 = 560. Cost to produce 700 parts = 700 * 36 = $25,200. Cost to repair 560 parts = 140 * 14 = $1,960. Total expected cost = $27,160
Here's the long way: solve for k first, given the half life of 7310 yrs. Assume A 0 = 1gm. A/A 0 = 1/2 = 1e 7310k Take the ln of both sides: ln(0.5) = 7310k
To find amount that is 20% greater, take amount from 2 years ago, 10.2 inches, and add 20% of 10.2 inches: 10.2 + 20% of 10.2 20% is 0.20 in decimal and "of" translates to multiplication, so