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  2. Decimal time - Wikipedia

    en.wikipedia.org/wiki/Decimal_time

    Since there are about 365 days in a year, there are about ⁠ 365 / 10 ⁠ = 36.5 days in a tenth of a year. Hence the year 2020.5 represents the day 2 July 2020. [ 22 ] More exactly, a "Julian year" is exactly 365.25 days long, so a tenth of the year is 36.525 days (36 days, 12 hours, 36 minutes).

  3. Time formatting and storage bugs - Wikipedia

    en.wikipedia.org/wiki/Time_formatting_and...

    In computer science, data type limitations and software bugs can cause errors in time and date calculation or display. These are most commonly manifestations of arithmetic overflow, but can also be the result of other issues. The most well-known consequence of this type is the Y2K problem, but many other milestone dates or times exist that have ...

  4. Calendar year - Wikipedia

    en.wikipedia.org/wiki/Calendar_year

    The Gregorian year, which is in use in most of the world, begins on January 1 and ends on December 31. It has a length of 365 days in an ordinary year, with 8760 hours, 525,600 minutes, or 31,536,000 seconds; but 366 days in a leap year, with 8784 hours, 527,040 minutes, or 31,622,400 seconds. With 97 leap years every 400 years, the year has an ...

  5. IRIG timecode - Wikipedia

    en.wikipedia.org/wiki/IRIG_timecode

    IRIG J-1 timecode consists of 15 characters (150 bit times), sent once per second at a baud rate of 300 or greater: <SOH>DDD:HH:MM:SS<CR><LF>. SOH is the ASCII "start of header" code, with binary value 0x01. DDD is the ordinal date (day of year), from 1 to 366. HH, MM and SS are the time of the start bit.

  6. Year 2038 problem - Wikipedia

    en.wikipedia.org/wiki/Year_2038_problem

    The year 2038 problem (also known as Y2038, [ 1] Y2K38, Y2K38 superbug or the Epochalypse[ 2][ 3]) is a time computing problem that leaves some computer systems unable to represent times after 03:14:07 UTC on 19 January 2038. The problem exists in systems which measure Unix time —the number of seconds elapsed since the Unix epoch (00:00:00 ...

  7. Year - Wikipedia

    en.wikipedia.org/wiki/Year

    In a non-leap year, there are 365 days, in a leap year there are 366 days. A leap year occurs every fourth year during which a leap day is intercalated into the month of February. The name "Leap Day" is applied to the added day. In astronomy, the Julian year is a unit of time defined as 365.25 days, each of exactly 86,400 seconds (SI base unit ...

  8. System time - Wikipedia

    en.wikipedia.org/wiki/System_time

    For example, the Unix system time 1 000 000 000 seconds since the beginning of the epoch translates into the calendar time 9 September 2001 01:46:40 UT. Library subroutines that handle such conversions may also deal with adjustments for time zones , daylight saving time (DST), leap seconds, and the user's locale settings.

  9. Metric time - Wikipedia

    en.wikipedia.org/wiki/Metric_time

    0.17 minutes 10 2: hectosecond: 100: 1.67 minutes (or 1 minute 40 seconds) 10 3: kilosecond: 1 000: 16.7 minutes (or 16 minutes and 40 seconds) 10 6: megasecond: 1 000 000: 11.6 days (or 11 days, 13 hours, 46 minutes and 40 seconds) 10 9: gigasecond: 1 000 000 000: 31.7 years (or 31 years, 252 days, 1 hour, 46 minutes, 40 seconds, assuming that ...