Search results
Results From The WOW.Com Content Network
Answer link. The region to the left of 0. The type of graph will depend on whether is it a simple number line graph, or on a set of x-y- axes. On a number line graph, we would start with an open circle on 0, because 0 IS NOT included in the solution. Draw a line extending to the left, indicating that x can be any value to the left of 0.
There is no x such that e^x = 0 The function e^x considered as a function of Real numbers has domain (-oo, oo) and range (0, oo). So it can only take strictly positive values. When we consider e^x as a function of Complex numbers, then we find it has domain CC and range CC "\\" { 0 }. That is 0 is the only value that e^x cannot take. Note that e^(x+yi) = e^x e^(yi) = e^x(cos y+i sin y) We have ...
Answer link. x=pi/2+kpi, k in ZZ In the trigonometric circle you will notice that cos (x)=0 corresponds to x=pi/2 and also x=-pi/2. Additionally to these all the angles that make a complete turn of the circle (2kpi) plus +-pi/2 correspond to cos (x)=0. So you have: x=+-pi/2+2kpi, k in ZZ If you try to see which are the first elements (from k =0 ...
So, whenever sinx = 0, we have that: x = π ± kπ for all k in the set of integers. That is, if k = 0,1,2,...,N, where N is some arbitrarily large integer, then sinx = 0 for x = 0, ± π, ± 2π,..., ± 2N π. Answer link. EZ as pi. May 19, 2017. 0° or any multiple of 180°. If sinx = 0, then x = 0°.
For an answer to have an infinite solution, the two equations when you solve will equal 0=0. Here is a problem that has an infinite number of solutions. 3x+2y= 12 -6x-4y=24 If you solve this your answer would be 0=0 this means the problem has an infinite number of solutions. For an answer to have no solution both answers would not equal each other. Here is a problem that has no solution. 4x-8y ...
lim x→a f (x) g(x) = lim x→a f '(x) g'(x) So we have: lim x→0 x sinx = lim x→0 1 cosx = 1 cos0 = 1 1 = 1. NOTE. The question was posted in "Determining Limits Algebraically" , so the use of L'Hôpital's rule is NOT a suitable method to solve the problem. Therefore this solution is invalid. ANSWER TO THE NOTE. This limit can not be ...
lim x→0+ xlnx = lim x→0+ lnx 1 x = lim x→0+ − 1 x 1 x2 = lim x→0+ −x = 0. You could probably figure out other ways to evaluate this limit, maybe using the squeeze theorem with upper bound x2 and something else for your lower bound, but L'Hopital's rule is how everyone would evaluate this limit. Answer link. There is no limit as x ...
Newton's Method is a mathematical tool often used in numerical analysis, which serves to approximate the zeroes or roots of a function (that is, all x:f (x) = 0). The method is constructed as follows: given a function f (x) defined over the domain of real numbers x, and the derivative of said function (f '(x)), one begins with an estimate or ...
There is another way to solve sin 3x = 0. Use the trig identity: sin3x = 3sinx − 4sin3x. sin3x = sinx(3 −4sin2x) a. sin x = 0 --> x = 0, and x = π, and x = 2π. b. (3 − 4sin2x) = 0. 4sin2x = 3. sin2x = 3 4 --> sinx = ± √3 2. - When sinx = √3 2 --> x = π 3 and x = 2 π 3. - When sinx = − √3 2 --> x = − π 3 and x = −2 π 3.
On the graph of a function f (x), a vertical asymptote occurs at a point P = (x0,y0) if the limit of the function approaches ∞ or −∞ as x → x0. For a more rigorous definition, James Stewart's Calculus, 6th edition, gives us the following: "Definition: The line x=a is called a vertical asymptote of the curve y = f (x) if at least one of ...