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Mar 17, 2011. #6. It's not going to generate you any postcodes of the form XX# #XX eg CB1 1AB. Which will probably exclude a significant proportion of addresses (every postcode I've had has been in this form). (I realise this is what you specified originally - just wondered if it was what you actually required though.)
Jul 19, 2012. #5. If you want to not have duplicates, and not do a visual basic arrangement, you might try putting 100000 in a1, putting a1 + INT (rand ()*17) in a2, copying a2 down the rest of of the column. Then in column B, rand ()*10000, and sort by column b.
Messages. 24,355. Jun 9, 2011. #7. If the questions are in column A and you want to select 50 questions at random you could put. =RAND ()< (50/COUNTA (A:A)) in the cells of a helper column and filter that on TRUE. 0.
Using your mapping function, 1/2 of the times (when your normal random number < 0.5) your formula min+2*rand* (mean-min) will generate a *uniformly* distributed random number between min and 2*mean-min. Similarly, you will generate a different random number that too will be uniformly distributed when your first normal random variable is > 0.5.
Good Weights: 0.9 0.7 Bad Weights: 0.5 0.2 0.1 Then, you fill each row such that the sum of the weights in the row equals the total weight. In this case, the total weight is 2.5, so the first row would be filled with 0.9 and 0.7, and the second row would be filled with 0.5, 0.2, and 0.1. Now, to generate a weighted random number, you randomly ...
What you need to do is generate a uniform distribution of random numbers and then transform them to a normal distribution with the required mean and standard deviation. If you generate a column of random numbers using RAND () and then use the function NORM.INV that will do the job. NORM.INV takes 3 parameters, one is the random number generated ...
RandomTriangular = Minimum + Sqr(CumulativeProb * LowerRange * TotalRange) Else. RandomTriangular = Maximum - Sqr((1 - CumulativeProb) * HigherRange * TotalRange) End If. End Function. The notes Mike posted are below (the code was A)... (B) The function above uses the (standard) inverse cumulative method for generating a random number.
Is it possible to generate a set of random numbers between say 50 - 150 whereby the sum of those random numbers totals a value in the spreadsheet which is determined by two other values in the spreadsheet? Eg: value 1 = 10, value 2 = 300. The difference = 290. Now generate 6 or so random numbers between 50 - 150 that come to a total of 290.
Hi, I was hoping to use vba to generate a random code that will contain both letters and numbers, being 9 characters long. Its going to be a part of a userform so the random code generated will populate a textbox within the userform. Many thanks in advance to any help you can give, Mike
I want to generate 2 random numbers bewteen 1 and 5, with 13 repetitions. The seond number can't be the as the first. So in Column A1 I would put =randbetween(1,5). In B1, I want to generate another random number between 1 and 5, but exclude the result in A1. Basically, I'm trying to randomly pick TWO days of the week, weekdays only Mon-Fri.