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Postby Chem_Mod » Sat Sep 03, 2011 9:48 am. Answer: Cancel out the 1/mol unit by dividing by the Avogadro constant. Then convert kJ to J by multiplying the kJ value by 1000 (because of the conversion factor 1 kJ = 1000 J). Top.
Postby Jenna Ortiguerra 4G » Wed Nov 06, 2019 12:56 am. To convert 4.89x10^-17 J to kJ/mol, you would indeed multiply by 0.001 to convert fromJ to kJ, which would leave you with kJ. If you divide by avogardo's number, it would cancel out the kJ which would leave you with moles. Top.
Both work but I'd be careful to convert all your units to the same scale (either joules or kilojoules) because the equations we use for entropy give us the answer in joules whereas the equations we use to calculate enthalpy frequently use kilojoules. Top. pmokh14B. Posts: 107. Joined: Sat Aug 17, 2019 7:15 am.
Set up the problem using J because that is the standard unit for energy, but you can either leave your answer in J or convert to kJ if youu want. Top. Jessica Jones 2B. Posts: 80. Joined: Fri Sep 29, 2017 2:04 pm.
It's definitely J.K^-1 by default, but if you are using the equation delta G = delta H - T*delta S, you will most likely need to convert the units of delta S to kJ.mol^-1 so you can subtract it from the change in enthalpy.
Postby PranitKumaran1F » Thu Feb 21, 2019 11:57 pm. Delta G is the measure of the change in free energy in a reaction, so you would use either J or KJ; However, you use KJ/mol or J/mol as the units when in respect to a certain number of moles of the species in the reaction. Top.
Postby Chem_Mod » Tue Aug 30, 2011 8:34 am. To change from units of L atm to Joules, multiply the gas constant 8.31447 J/mol K and divide by the gas constant 0.08206 L atm/mol K. This is the same as multiplying by 1/1, since the gas constants are the same value with different units. If you do this, you will notice that 1 L atm = 101.325 J.
Hi! It depends on what the units are in your calculations, so sometimes you will use R=8.314 J/Kmol and sometimes you will use R=0.08206 Latm/Kmol. Usually if you're using the PV=nRT equation for an ideal gas calculation, you'll use 0.08206 Latm/Kmol because the units match up with the other units in the equation. Hope this helps!
Postby Aparna Pillai 1E » Sun Oct 31, 2021 4:45 am. Yes. After converting eV/atom to kJ/atom, you would then divide by 6.02 × 10^23 atoms/mol to get units of kJ/mol. Top.
ΔH=qp. However, questions can word it in the following ways to signify kJ/mol. Molar enthalpy. ΔH: kJ/mol. Standard enthalpy of reaction. ΔH∘rxn: kJ/mol. Standard enthalpy of formation. ΔH∘f: kJ/mol. Note: In my understanding, "standard", signifies or corresponds to the formation of 1 mol product, so that could be a keyword you would ...