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  2. Coupon collector's problem - Wikipedia

    en.wikipedia.org/wiki/Coupon_collector's_problem

    Coupon collector's problem. In probability theory, the coupon collector's problem refers to mathematical analysis of "collect all coupons and win" contests. It asks the following question: if each box of a given product (e.g., breakfast cereals) contains a coupon, and there are n different types of coupons, what is the probability that more ...

  3. List of yarns for crochet and knitting - Wikipedia

    en.wikipedia.org/wiki/List_of_yarns_for_crochet...

    Yarn size. Depending on the exact yarn weight and the gauge of the knitter or crocheter and how tight or loose the yarn is held, the gauge listed below can vary.The type of yarn can also affect the look of the item, so if it’s thicker yarn the item will look bulkier compared to yarn that is thinner. For this reason it is important to check ...

  4. Crochet - Wikipedia

    en.wikipedia.org/wiki/Crochet

    The thickness or weight of the yarn is a significant factor in determining how many stitches and rows are required to cover a given area for a given stitch pattern. This is also termed the gauge. Thicker yarns generally require large-diameter crochet hooks, whereas thinner yarns may be crocheted with thick or thin hooks.

  5. Yarn weight - Wikipedia

    en.wikipedia.org/wiki/Yarn_weight

    A way of determining the weight of an unknown yarn is to use the wrapping method. This method is also used to calculate the amount of yarn needed for a project. By this method it is possible to check an unknown weight of yarn with a regular pencil and ruler [3] without unwinding the yarn. Simply slip the pencil under approximately an inch of ...

  6. Equations for a falling body - Wikipedia

    en.wikipedia.org/wiki/Equations_for_a_falling_body

    The first equation shows that, after one second, an object will have fallen a distance of 1/2 × 9.8 × 1 2 = 4.9 m. After two seconds it will have fallen 1/2 × 9.8 × 2 2 = 19.6 m; and so on. The next-to-last equation becomes grossly inaccurate at great distances. If an object fell 10 000 m to Earth, then the results of both equations differ ...

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